A hemispherical bowl of diameter 36 cm contains liquid. This liquid is filled into 72 cylindrical bottles of diameter 6 cm. Find the height of each bottle, if 10% of liquid is wasted in this transfer.
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AnnaMavericks:
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Volume of hemispherical bowl = 2/3 pie r^3
= 2/3 × 22/7 × 18× 18 × 18
= 12208.3
Now 10% wasted
So 90% left
Which is filled in 72 cylindrical of radius 3
0.9 × 12208.3 = pie r^2 h × 72
10987.47 = 3.14 × 9 × 72 × h
10987.47 = 2034.72 h
h= 5.399
= 2/3 × 22/7 × 18× 18 × 18
= 12208.3
Now 10% wasted
So 90% left
Which is filled in 72 cylindrical of radius 3
0.9 × 12208.3 = pie r^2 h × 72
10987.47 = 3.14 × 9 × 72 × h
10987.47 = 2034.72 h
h= 5.399
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