Question

$\huge\blue{զմҽsԵíօղ}$
a body of mass 10kg is acted on by a constant force of 20N for 3 seconds. calculate the kinectic energy at the end of the time.

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Answer 1

ANsWeR :-

a = F/m = 20/10 = 2 m/s^2

d = (1/2) a t^2 = (1/2)(1) (3*3) = 9 meters

work done = force * distance = 10 × 9 = 90 Joules

gain in kinetic energy = work done.

Answer 2

${\tt{\red{\underline{\underline{\huge{AnswEr}}}}}}$

a = F/m = 20/10 = 2 m/s^2

d = (1/2) a t^2 = (1/2)(1) (3*3) = 9 meters

work done = force * distance = 10 * 9 = 90 Joules

gain in kinetic energy = work done

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