Question

$\huge\blue {\underline { \overline{ \bf \mid\: \: \: \: \: QUESTION \: \: \: \: \mid}}}$



Formula of alpha decay is​

Answer 1

Explanation:

Alpha Decay Formula

_{Z}^{A}\textrm{X} is the parent nucleus. _{Z-2}^{A-4}\textrm{X'} is the daughter nucleus. _{2}^{4}\textrm{α} is the emitted alpha particle.

Answer 2

Explanation:

equation. For the decay reaction 238U → 234Th + 4He, the mass values for 238U and 4He are in Table 3.1; for 234Th it is 234.043 594. Thus we obtain Qα = –931.5 (234.043 594 + 4.002 603 – 238.050 7785) = 4.274 MeV.