Question

$\huge\bold{A.}$$\large{\sf{\pink{Develop\:meaningful\:stories}}}$
$\large{\sf{\pink{from\:the\:given\:outlines.}}}$
$\longrightarrow$ Robert Bruce .... . .. .. .. King of Scotland ...... .... . the English King attacks .. ...... ..Bruce defeated ..... ... ... tries many times ....... .... fails ....... .... runs away to a forest ...... ... .. sits in a cave .. .... ..... sees a spider ........... trying to reach the web ...... .. ... many attempts..... .... .. succeeds .. . . .. .. . .. Bruce gets encouragement ....... .. .. returns. .. .. .. . . . . collects an army ... ........ attacks England .... ....... defeats ..... .. .... gets back his kingdom.
$\huge{\fbox{\fbox{Xx\:No\:spam\:xX}}}$

Answer 1

Robert Bruce was the king of Scotland. He was living peacefully in his kingdom. But one day, the English king decided to attack Bruce's kingdom. After a huge war Bruce got defeated by the English king. But he didn't lose his strength, he tried so many times to defeat the English king but failed. After being defeated so may times, Bruce ran away to a forest and started to search for a place. After sometime he saw a cave and decided to spend the night there. As Bruce was sitting in the cave he saw a small spider who was trying to reach a web. The spider was tried many times and finally succeeded. Seeing all this gave encouragement to Bruce. He decided to return to the kingdom and to try again. He started collecting army while going to the kingdom. After some days, he and his armies attacked England. As this time, Bruce has more armies, he succeeded in defeating England. He got his kingdom back and started living peacefully again.

Explanation:

Hope is will help u

Answer 2

Explanation:

$</p><p> </p><p></p><p>\begin{gathered}\dashrightarrow\sf\:\:(Diagonal)^2=(Length)^2+(Breadth)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=(BC)^2+(CD)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=(24\:cm)^2+(7\:cm)^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=576\:cm^2+49\:cm^2\\\\\\\dashrightarrow\sf\:\:(BD)^2=625\:cm^2\\\\\\\dashrightarrow\sf\:\:BD=\sqrt{625\:cm^2}\\\\\\\dashrightarrow\sf\:\:BD=\sqrt{25\:cm \times 25\:cm}\\\\\\\dashrightarrow\:\:\underline{\boxed{\sf BD=25\:cm}}\qquad\bigg\lgroup\bf Diagonal\bigg\rgroup\end{gathered} </p><p>⇢(Diagonal) </p><p>2</p><p> =(Length) </p><p>2</p><p> +(Breadth) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =(BC) </p><p>2</p><p> +(CD) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =(24cm) </p><p>2</p><p> +(7cm) </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =576cm </p><p>2</p><p> +49cm </p><p>2</p><p> </p><p>⇢(BD) </p><p>2</p><p> =625cm </p><p>2</p><p> </p><p>⇢BD= </p><p>625cm </p><p>2</p><p> </p><p> </p><p> </p><p>⇢BD= </p><p>25cm×25cm</p><p> </p><p> </p><p>⇢ </p><p>BD=25cm</p><p> </p><p> </p><p> </p><p> </p><p>⎩</p><p>⎪</p><p>⎪</p><p>⎪</p><p>⎧</p><p> </p><p> Diagonal </p><p>⎭</p><p>⎪</p><p>⎪</p><p>⎪</p><p>⎫</p><p> </p><p> </p><p> </p><p> </p><p></p><p>⠀</p><p></p><p>\therefore\:\underline{\textsf{Hence, Length of Diagonal is C) \textbf{25 cm}}}.∴ </p><p>Hence, Length of Diagonal is C) 25 cm</p><p> </p><p> .$