Question

$\huge\bold \color{brown}{( \int^{a}_{1} (2x) - 1dx)dx = 6}$


❖ᴏɴʟʏ ᴘʀᴏᴘᴇʀ ꜱᴏʟᴠᴇᴅ ᴀɴꜱᴡᴇʀ ᴡɪᴛʜ ɢᴏᴏᴅ ᴇxᴘʟᴀɴᴀɪᴏɴ ɴᴇᴇᴅᴇᴅ
❖ ɴᴏ ꜱᴘᴀᴍᴍɪɴɢ
❖ᴏɴʟʏ ꜰᴏʀ ᴍᴏᴅᴇʀᴀᴛᴏʀꜱ, ʙʀᴀɪɴʟʏ ꜱᴛᴀʀꜱ ᴀɴᴅ ᴏᴛʜᴇʀ ʙᴇꜱᴛ ᴜꜱᴇʀꜱ​​​​​​​​​​​​​​​​​​​​​​​​​

Answer 1

$\bold{{( \int^{a}_{1} (2x) - 1dx)dx = 6}}$

$\bold{( \int^{a} _{1}2xdx + \int^{a}_{1} - 1dx)dx}$

$\bold{2( \int^{a} _{1}xdx + \int^{a}_{1} - 1dx)dx}$

$\bold{ (2( \frac{1}{x} {x}^{2} ] {}^{a}_{1}) + \int {}^{a}_{1} - 1dx)dx}$

$\bold{ (2( \frac{ {x}^{2} }{2}] {}^{a}_{1}) + \int {}^{a}_{1} - 1dx)dx}$

$\bold{ (2( \frac{ {x}^{2} }{2}] {}^{a}_{1}) + - x] {}^{a}_{1}})dx$

$\bold{(2(( \frac{ {a}^{2} }{2} ) - \frac{ {1}^{2} }{2} ) + - x] {}^{a} _{1})dx}$

$\bold{(2( \frac{ {a}^{2} }{2} - \frac{ {1}^{2} }{2} ) + (- a) + 1 \times 1)dx}$

$\bold{(2( \frac{1}{2} {a}^{2} - \frac{1}{2} ) - a + 1)dx}$

$\bold{(2( \frac{ {a}^{2} }{2} - \frac{1}{2} ) - a + 1)dx}$

$\bold{(2\frac{ {a}^{2} }{2} + 2( - \frac{1}{2} ) - a + 1)dx}$

$\bold{{a}^{2} + 2( - \frac{1}{2} ) - a + 1)dx}$

$\bold{{a}^{2} - {1} - a + 1}$

$\bold{{(a}^{2} - a + 0)dx}$

$\bold{{(a}^{2} - a )dx}$

$\bold{{(a}^{2}d - a d)x}$

$\bold{{a}^{2}dx - a dx}$

Answer 2

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