Question

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The incomplete table above summarizes the number of left-handed students and right-handed students by gender for the eighth grade students at Keisel Middle School. There are 5 times as many right-handed female students as there are left-handed female students, and there are 9 times as many right-handed male students as there are left-handed male students. if there is a total of 18 left-handed students and 122 right-handed students in the school, which of the following is closest to the probability that a right-handed student selected at random is female? (Note: Assume that none of the eighth-grade students are both right-handed and left-handed.)

A) 0.410
B) 0.357
C) 0.333
D) 0.250​

Answer 1

Answer:

a)357

Step-by-step explanation:

Hope this will help you

Answer 2

$\huge \bold \color{lime}\maltese\color{orange}A \color{red}n \color{green}s \color{blue}w \color {purple} e \color {yellow} r\color{lime} \maltese$

Let,

no. of left handed female students be x

no. of left handed male students be y

Total no. of left handed students = 18

i.e., x+y=18 (i)

then, no. of right handed female students = 5x

no. of right handed male students 9y

Total no. of right handed students = 122

i.e., 5x + 9y = 122

(ii)Multiplying (i) and 5 we get 5x + 5y = 90

(iii)Subtracting (ii) from (iii) we get -4y = -32

$y = \frac{ - 32} {- 4} = 8$

Apply y = 8 (i)

x+ 8 = 18

x = 18 - 8 = 10

no. of right handed female students = 5 x 10 = 50

$Probability\: of \: selected \: student \: is \: right \\ handed \: female \: students = \frac{50}{122} \\ = 0.40983... =0.410$

The correct answer is option (A) 0.410