Physics, asked by ToxicEgo, 2 days ago

\huge\bold\purple{Question} Saméër drives North for 35 minutes at 85 km/hr and then stops at Sïddhí's house for 15 minutes. He next continues North, travelling 130 km in 2 hours. What is his total displacement?​

Answers

Answered by sukhpreetsingh7717
8

Answer:

179.6 km

Given,

Displacement in first event = speed×time= 85 ×35/60

=49.58km

Displacement in second event = 130 km

Net displacement D=49.58+130=179.58km

Explanation:

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Answered by Ᏸυէէєɾϝɭყ
12

Answer:

A motorist drives north for 35.0 minutes at

85.0 km/h and then stops for 15.0 minutes.

He next continues north, travelling 130 km in

2.00 hours. What is his total displacement

 

ᴄᴀsᴇ1:

  • 85ᴋᴍᴘʜ =23.611 ᴍ/s
  • 35 ᴍɪɴ=0.583ʜʀ

ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟʟᴇᴅ ɪɴ ғɪʀsᴛ ᴄᴀsᴇ =

  •  0.583x85=49.555

ᴄᴀsᴇ 2:

  • 130 ᴋᴍ ɪɴ 2ʜʀs 
  • ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟʟᴇᴅ = 130ᴋᴍ

ғɪɴᴀʟʟʏ ᴛᴏᴛᴀʟ ᴅɪsᴛᴀɴᴄᴇ ᴛʀᴀᴠᴇʟʟᴇᴅ ʙʏ sᴀᴍᴇᴇʀ ɪs = 130+49.555=179.555=179.6

 Explanation:

ᴛ1=0.583 ʜʀ

ᴛ2=2 ʜʀ

s1=49.555 ᴋᴍ

s2=130 ᴋᴍ

sɴᴇᴛ=179.6

ᴠ1=23.611ᴍ/s=85ᴋᴍᴘʜ

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