Question

$\huge \bold{Question:-}$
Calcium carbonate reacts with aqueous HC1 to give CaCl2 and C02 according to the reaction given below:
$\small \tt{CaC0_3(s) + 2HCl(aq) → CaCl_2(aq) + C0_2(g) + H2_O(l)}$
$\bold{To \: Find:-}$
•What mass of CaCl2 will be formed when 250 mL of 0.76 M HC1 reacts with 1000 g of CaC03?
•Name the limiting reagent. •Calculate the number of moles of CaCl2 formed in the reaction.

$\large \bold{@WildCat7083}$​

Answer 1

Answer:

Calcium carbonate reacts with aqueous HCl to give CaCl_(2) and CO_(2) according to the reaction given below <br> CaCO_(3)(s)+2HCl(aq)rarrCaCl_(2)(aq)+CO_(2)(g)+H_(2)O(l) <br> What mass of CaCl_(2) will be formed when 250mL of 0.76 M HCl reac ts with 1000 g of CaCO_(3)?

Explanation:

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Answer 2

Answer:

sister did u die? :c

dnt abandoned meeeeeeeeeee T-T me smoll and innocent and still a baby w a attitude u cant leave what if somebody trynna fight me and i try 2 kill them T-T u da only 1 dat can calm me down peke

Explanation: