Math, asked by Anonymous, 3 months ago

\huge\bold{Question}

From a rope 11 m, two pieces of lengths 18 ÷ 5m and 13 ÷ 10 m are cut off. What is the length of the remaining rope?​

Answers

Answered by Anonymous
575

\huge\bold{Solution}

18/5 = 3.6

33/10 = 3.3

3.6 + 3.3 = 6.9

11 - 6.9 = 4.1

Hope it's helpful :)


xXAbhiSharma45Xx: hi I am here
Answered by xXAbhiSharma45Xx
2

\huge{\underline{\red{\mathfrak{♡Answer♡}}}}

Cut off cut off from 11m

2 3/5 +3 3/10

13/5 +33/10

(26+33)/10

59/10 m

Length of remaining= 11-59/10

(110 -59)/10

51/10

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