Question

$\huge\bold{Question}$
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the half- life of substance in certain enzyme catalysed reaction is 138 seconds. the time required for the concentration of the substance to fall from 1.28 mgL^-1 to 0.04mgL^-1is

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Answer 1

Fall from 1.28 mg L^{–1}
to 0.04 mg L^{–1}involves five half-lives.

Time-required = 5 × t_{1/2}

= 5 × 138 s

= 690 s

Answer 2

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