Question

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What is the probability that a leap year selected at random will contain 53 Sundays ?


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Answer 1

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There are 366 days in a leap year that contain 52 weeks and 2 more days. So, 52 Sundays and 2 days.

These 2 days can be:

(Mon, Tue}, {Tue, Wed}, {Wed, Thu}, {Thu, Fri}, {Fri, Sat}, {Sat, Sun} and {Sun, Mon} - 7 cases. 

In order to have 53 Sundays we should have either {Sat, Sun} or {Sun, Mon} case. 

No. of sample spaces = 7.

No. of event that gives 53rd Sunday in Leap Year = 2.

Required Probability = 2⁄7 ☺✌

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Answer 2

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Favourable Outcomes = 2

Total no. of outcomes=7

P(that a leap year selected at random will contain 53 Sundays)= 2/7