Question

$\huge\bold \red{ \frac{d}{dx}\bigg( \frac{ {x}^{4} + 1}{ {x}^{2} } \bigg)}$


Only proper solved answer ​

Answer 1

$\frac{d}{dx}\bigg( \frac{ {x}^{4} + 1}{ {x}^{2} } \bigg)$

$\frac{d}{dx} {x}^{2}+\frac{1}{{x}^{2}}$

$(\frac{d}{dx} {x}^{2})+(\frac{d}{dx} \frac{1}{{x}^{2}})$

$2x+(\frac{d}{dx} \frac{1}{{x}^{2}})$

$2x-\frac{2}{{x}^{3}}$

Answer 2

Answer:

$\frac{d}{dx}\bigg( \frac{ {x}^{4} + 1}{ {x}^{2} } \bigg)$

$\frac{d}{dx} {x}^{2}+\frac{1}{{x}^{2}}$

$(\frac{d}{dx} {x}^{2})+(\frac{d}{dx} \frac{1}{{x}^{2}})$

$2x+(\frac{d}{dx} \frac{1}{{x}^{2}})$

$2x-\frac{2}{{x}^{3}}$