Question

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The question is

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Find the area of Rhombus whose side is 5cm whose attitude is 4.8cm.If one of its diagonals is 8cm ,find the length of other diagonal.

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Answer 1

Area of the rhombus = Side × Length of the altitude 
= 5*4.8
= 24 sq cm 
Now,
Let the length of the other diagonal = x
It is known that the area of a rhombus is half the product of its diagonals. 
∴ (1/2) × 8 × x = 24
⇒ 4x = 24
⇒ x = 6 cm
The length of the other diagonal is 6 cm.
Answer.

Answer 2

Rhombus
Side=5cm
Height=4.8cm

Area of parallelogram=b×h
=5×4.8
=24 cmsq.

Again
Area of rhombus =1/2×d1×d2
24=1/2×8×d2
24=4×d2
24/4=d2
6=d2

Therefore d2=6cm

The length of other diagonal is 6cm

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