Question

$\huge\bold\red{QUESTION}$
Two numbers are such that the ratio between them is 3:5 if each is increased by 10, the ratio between the new numbers so formed is 5:7 find the original number‽‽‽​

Answer 1

${\huge{\mathcal{\red{answer}}}}$

Let the ratio,3:5 be taken as 3x and 5x

BTP,

If the ratios are increased by 10 i.e,

3x+10 and 5x+10

BTP,

3x+10+5x+10=5x+7x

8x+20=12x

8x-12x=-20

-4x=-20

x=-20/-4

=5

Therefore,the original ratio 3x and 5x

3x=3×5=15

5x=5×5=25

Hope it helps!!

Answer 2

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$\text{\large\underline{\purple{Given:-}}}$

• To numbers are in the ratio 3:5.

• if each number is increased by 10 then the ratio of the new numbers is 5:7.

To Find :

original numbers

$\text{\large\underline{\orange{Solution:-}}}$

$\longmapsto\tt\bold{Let\:the\:first\:no.\:be=3x}$

$\longmapsto\tt\bold{Let\:second\:no.\:be=5x}$

A.T.Q -

if each number is increased by 10 then the ratio of the new numbers is 5:7.

$\longmapsto\tt\bold{\dfrac{3x+10}{5x+10}=\dfrac{5}{7}}$

$\longmapsto\tt\bold{7(3x+10)=5(5x+10)}$

$\longmapsto\tt\bold{21x+70=25x+50}$

$\longmapsto\tt\bold{21x-25x=50-70}$

$\longmapsto\tt\bold{-4x=-20}$

$\longmapsto\tt\bold{x=\cancel\dfrac{-20}{-4}}$

$\longmapsto\tt\bold{x=5}$

Value of x is 5...

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