Question

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ΔABC and A'B'C 'are given as shown in the figure. B'A'C '= ........​

Answer 1

Step-by-step explanation:

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\huge\bold\red{question}\ \textless \ br /\ \textgreater \question \textless br/ \textgreater ΔABC and A'B'C 'are given as shown in the figure. B'A'C '= ........

solution:-

B'A'C'=BAC

therefore,

2x+20=3x

and that is

3x-2x=20

therefore,B'A'C'= 2×20+20(putting the value of 'x' here)

= 60° answer

Answer 2

Answer:

As we now By angle sum property

In ∆B'A'C' = 60° +2x+20+y= 180°

= 2x-20+y = 120°

= 2x+y =100°. ....(1)

In ∆ABC = 60°+ 3x+ y = 180°

= 3x+y = 120°. ..(2)

Now , Subtract (2) from (1)

>> 3x+y = 120°

>>2x +y = 100°

___(-)_________

>>> x =20°

If x is 20°

then , angle A' = 2x+20= 60°

angle C' = 2x+y =100°. {from equation 1}

= 2(20) +y =100°

= y = 60°

SO ANGLES WILL BE 60° each in ∆B'A'C

Hence sides will be also 6 .

Hope it helps!!