If the side of a cubical box is increased by 250%.What will be change in its
i) Volume
ii) Total surface area
iii) Lateral surface area
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Step-by-step explanation:
Let the original side be a then
Original surface area S=6a2
When side is increased by 50%, side becomes 23a then
Surface area s=227a2
Hence,
Surface area is increases by x=6a2227a2−6a2×100=125%
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