Question

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No one is answering this question. i am posting it again. Hey, Physics Champs ! Help me to do this..

But Answer with proper Explanation is needed... ​

Answer 1

#Figures was in the attachment .

In First figure CD and CE resistors are connected in series.

Rp = 1 Ω + 1Ω

Rp = 2Ω

Now, calculation resistance of two resistors of 2nd figure In which R1 and R2 resistors are in parallel.

So,

1/Rp = 1/R1 + 1/R2

1/Rp = 1/2 + 1/2

1/Rp = 2/2

Rp = 1Ω

Now, calculating resistance of 3rd figure in which two resistors are connected in series .

Rp = 1Ω + 1Ω

Rp = 2Ω

Calculating resistance of 4th figure in which LM and EF are connected in parallel.

1/Rp = 1/R1 + 1/R2

1/Rp = 1/2 + 1/2

1/Rp = 2/2

Rp = 1Ω

Calculating resistance of 5th figure in which 2 resistors are connected in series

Rp = 1Ω + 1Ω

Rp = 2Ω

Calculating resistance of 6th figure in which 2 resistors are connected in parallel.

1/Rp = 1/R1 + 1/R2

1/Rp = 1/2 + 1/2

1/Rp = 2/2

Rp = 1Ω

Calculating resistance of 7th figure in which two resistors are connected in series.

Rp = 1Ω + 1Ω

Rp = 2Ω

At last Calculating resistance of 8th figure in which resistors are connected in parallel.

1/Rp = 1/R1 + 1/R2

1/Rp = 1/2 + 1/2

1/Rp = 2/2

Rp = 1Ω

Hence,

Equivalent resistance of the given figure is 1Ω

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Answer 2

Answer:

I have posted the correct answer once.I am posting the answer with explanation again