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# Figures was in the attachment.
- we need to calculate Equivalent resistance in the given circuit.
In 1st figure
AB , BC and AD are connected in series,
So,
→ Rs = 1Ω + 1Ω + 2Ω
→ Rs = 4Ω
Now,
In second figure Rs and DC are connected in parallel,
So,
→ 1/Rp = 1/Rs + 1/4
→ 1/Rp = 1/4 + 1/4
→ 1/Rp = 2/4
→ 1/Rp = 1/2
→ Rp = 2Ω
Now ,
In Third figure all r resistors are connected in series,
Then Total resistance R :-
→ R = Rp + 2Ω + 1Ω
→ R = 2Ω + 3Ω
→ R = 5Ω
Hence,
Equivalent resistance of given circuit is 5Ω
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