Question

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➡️ A proton and deutron having same kinetic energy enters perpendicularly in a magnetic field B. For motion of proton and deutron on circular path of radius Rp and Rd respectively. What will be the ratio of their radii ?


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Answer 1

Answer:

Radius of circular path  r=Bqmv

Using  p=mv=2mK

where K is the kinetic energy of the particle.

We get  r=Bq2mK

⟹  r∝qm

Given : qα=2qp and  qd=2qp   where qp is the charge of proton.

Also, mα=4mp  and  md=2mp where mp is the mass of proton.

∴ rp:rd:rα=qpmp:qdmd

Answer 2

Answer:

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