Physics, asked by rahul0067, 1 year ago

[tex]/huge/bold/The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s2. The distance covered by the body in the 5th second of its motion is ?[tex]

Answers

Answered by Dexteright02
4

Hello!

The initial velocity of a body moving along a straight line is 7 m/s. It has a uniform acceleration of 4 m/s². The distance covered by the body in the 5 th second of its motion is ?

* Find the distance, we have the following data:

Vi (initial velocity) = 7 m/s

t (time) = 5 s

a (acceleration) = 4 m/s²

d (distance) = ? (in m)

By the formula of the space of the Uniformly Varied Movement, it is:

d = v_i * t + \dfrac{a*t^{2}}{2}

d = 7 * 5 + \dfrac{4*(5)^{2}}{2}

d = 35 + \dfrac{4*25}{2}

d = 35 + \dfrac{100}{2}

d = 35 + 50

\boxed{\boxed{d = 85\:m}}\longleftarrow(distance)\:\:\:\:\:\:\bf\green{\checkmark}

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\bf\green{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}

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