Question

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A thief is running on a motorcycle at a constant speed of 25 m/s . A police jeep starts chasing from a point 1.25 km behind him with a uniform acceleration of 2m/s^2 .

➤Find :-

1. After how much time will the police catch the thief ?

2. How much distance will the jeep cover to reach the thief ?

3. What should be the minimum acceleration of the thief to escape from police ?





➡ Need a good answer !
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Answer 1

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police will catch the thief if distance travel by policein time t=1250m.+25t m.

using s=ut+1/2 at^2

u=0,a=2m.s^2

(1/2)*2 t^2=1250+25t

t^2-25t-1250=0

(t+25)(t-50)=0

so t=50 sec.

ɪ ᴍɪss ᴜ ᴍᴇʟɪ ᴊᴀᴀɴ

Answer 2

Answer:

police will catch the thief if distance travel by policein time t=1250m.+25t m.

using s=ut+1/2 at^2

u=0,a=2m.s^2

(1/2)*2 t^2=1250+25t

t^2-25t-1250=0

(t+25)(t-50)=0

so t=50 sec.

hope it's helpful to you☺