Question

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A truck of mass 5000 kg moving with a velocity of mass 90 km/h hits a wall

and comes to rest in 25 second find the force exerted by the car on the wall.

Don't copy from Google or any other app.

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Answer 1

Given :-

A truck of mass 5000 kg moving with a velocity of mass 90 km/h hits a wall  and comes to rest in 25 second.

To Find :-

The force exerted by the car on the wall.

Analysis :-

First, find the acceleration by considering it as a variable by substituting it using the first law of motion.

Then, find the force by it's respective formula.

Solution :-

We know that,

• a = Acceleration
• v = Final velocity
• u = Initial velocity
• f = Force
• m = Mass
• t = Time

By the formula,

$\underline{\boxed{\sf First \ law \ of \ motion=v=u + at}}$

Given that,

Initial velocity (u) = 90 km/h = 25 m/s

Time (t) = 25 sec

As the truck comes to rest,

Final velocity (v) = 0

Substituting their values,

$\sf 0=25+25a$

$\sf -25=25a$

Finding the value of a,

$\sf a=\dfrac{-25}{25}$

$\sf a=-1 \ m/s^{2}$

Therefore, the acceleration is -1 m/s².

By the formula,

$\underline{\boxed{\sf Force=Mass \times Acceleration}}$

Given that,

Mass (m) = 5000 kg

Acceleration (a) = -1 m/s²

Substituting their values,

Force = 5000 × -1

Force = -5000 N

Therefore, the force exerted by the car on the wall is -5000 N.

Answer 2

Answer is 5000N

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