Question

${ \huge{ \boxed{ \frak { \green{question}}}}}$
Given
$log_{10}2 = \: 0.30103$
$log_{10}e = 0.43429$


Then find the value of
$log_{e}125 + log_{3}81 + {e}^{ log_{e}2}$



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Answer 1

Step-by-step explanation:

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Answer 2

ANSWER IN THE ATTACHMENT.