Question

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1) What is the least fraction that must be added to
$1 \times \frac{1}{3} \div 1 \times \frac{1}{2} 1 \times \frac{1}{9}to \: make \: the \: result \: \\ an \: integer | \\ \\( hint || solve \: 1 \times \frac{1}{3} \div 1 \times \frac{1}{2} \div 1 \times \frac{1}{9} \\ and \: subtract \: from \: the \: nearest \: \\ integer \: value \: )$
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Answer 1

First, change the mixed fractions into improper fractions by multiplying the whole number by the denominator and then adding the numerator.

2 1/3=2×3+1/3=7/3

1 1/2=1×2+1/2=3/2

Next, find a common denominator and then multiply the top and the bottom by the same number.

7/3×2/2=14/6

3/2×3/3=9/6

Subtract the numerators.

14−9=5

Make sure to keep the denominator.

5/6

Answer 2

Step-by-step explanation:

The above answer is correct