In the figure,
measure angle RST = (x + 20)°
measure angle BSR = (2x + 10)°
then measure angle ARP = how much?
(line AC || line AD)
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Answered by
3
Answer:
In the figure,
measure angle RST = (x + 20)°
measure angle BSR = (2x + 10)°
then measure angle ARP = how much?
(line AC || line AD)
Step-by-step explanation:
sorry I don't hAve much time cuz I'm in bed
Answered by
17
Answer:
Angle(RSD) = 70° , Angle(BSR) = 110°, Angle(ARP) = 110°.
Step-by-step explanation:
Angle(RSD) and Angle(BSR) forms a supplimentary/linear pair of angles. That is, their sum must be equal to 180°.
Thus, Angle(RSD) + Angle(BSR) = 180°
(x+20) + (2x+10) = 180°
3x + 30 = 180°
3x = 150°
x = 150/3 = 50°
Therefore,
- Angle(RSD) = x+20 = 50+20 = 70°.
- Angle(BSR) = 2x+10 = 2*50 +10 = 100+10 = 110°.
Since, AC || AD and PS is the transversal. Angle(ARP) and Angle (BSR) forms a pair of corresponding angles, and hence are equal to one another.
That is, Angle(ARP) = Angle(BSR) = 110°.
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