Math, asked by samiksha5055, 1 month ago


 \huge \boxed { \mathfrak \pink{solve}:}

In the figure,
measure angle RST = (x + 20)°
measure angle BSR = (2x + 10)°
then measure angle ARP = how much?
(line AC || line AD) ​

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Answers

Answered by renukahulihalli007
3

Answer:

In the figure,

measure angle RST = (x + 20)°

measure angle BSR = (2x + 10)°

then measure angle ARP = how much?

(line AC || line AD)

Step-by-step explanation:

sorry I don't hAve much time cuz I'm in bed

Answered by Anonymous
17

Answer:

Angle(RSD) = 70° , Angle(BSR) = 110°, Angle(ARP) = 110°.

Step-by-step explanation:

Angle(RSD) and Angle(BSR) forms a supplimentary/linear pair of angles. That is, their sum must be equal to 180°.

Thus, Angle(RSD) + Angle(BSR) = 180°

(x+20) + (2x+10) = 180°

3x + 30 = 180°

3x = 150°

x = 150/3 = 50°

Therefore,

  • Angle(RSD) = x+20 = 50+20 = 70°.
  • Angle(BSR) = 2x+10 = 2*50 +10 = 100+10 = 110°.

Since, AC || AD and PS is the transversal. Angle(ARP) and Angle (BSR) forms a pair of corresponding angles, and hence are equal to one another.

That is, Angle(ARP) = Angle(BSR) = 110°.

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