Question

$\huge\boxed{\mathfrak\red{QUESTION:-}}$


what will be the power consumption of two 300 W bulbs,three 100 W fans and one 1200 W refrigerator for continuous operation of 30 hours ?​

Answer 1

To Find:

Power consumption.

Power two bulbs = 2 x 300 = 600 W

Power of three fans = 3 x 100 = 300 W

Power of one refrigerator = 1200 W

• Total time = 30 hours

We know that:

Power consumption = Total power x Total

time

Finding the power consumption:

Power consumption = (600 + 300 + 1200) x 30

Power consumption = 2100 x 30

Power consumption = 63000

Power consumption = 63000 Watt-hour

Converting power consumption in kWh:

1000 Wh = 1 kWh

. 63000 Wh = 63000/1000 kWh

. 63000 Wh = 63 kWh

Hence,

• The power consumption will be 63.

Hope it helps:)

Answer 2

Answer:

Energy = Power*time

Energy consumed by 100 W bulb per day=2∗100Wh

= 0.2 kWh

Energy consumed by 40 W bulbs per day

=4∗40∗4 Wh

= 0.64 kWh

Total energy consumed per day = 0.2 + 0.64 kWh

= 0.84 kWh

Therefore, the energy consumed in 30 days =30∗0.84 kWh

= 25.2 kWh

♓hopes its helps you..

Explanation: