Question

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Question in Attachment​

Answer 1

Answer:

hope this will help you

Answer 2

$\huge\mathcal{\boxed{\underline{\color{olive} Good\: Evening}}}$

$\huge\mathcal{\underline{\color{aqua}QUESTION}}$

⭐ The molarity of a commercial sample of 67.2 volume $\sf{H_2O_2}$ solution is _ .

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☕ The expression for the molarity is,

$\red\bullet\:\bf\purple{Molarity\:=\:\dfrac{'x'~volume}{11.2}\:}$

Where,

• $\bf\pink{'x'~volume}$ = 67.2

$\bf{\implies\:Molarity\:=\:\dfrac{67.2}{11.2}\:}$

$\bf\gray{\implies\:Molarity\:=\:6\:M}$

✔️ Therefore, the molarity of a commercial sample of 67.2 volume $\sf{H_2O_2}$ solution is “6M” .