Question

${\huge{\boxed{\mathtt{\green{answer \: those \: please \: }}}}}$
$\large\sf\red{help \: please}$
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Answer 1

$\underline{ \underline{ { \huge{\rm{S}}} \sf{olution \: -} }}$

$\sf \: a) \: \frac{2}{3} + \frac{1}{7 } \\ \\ \sf \implies \: LCM \: of \: 3 \: and \: 7 \: is \: 21. \\ \sf \implies \: \frac{2 \times 7 + 1 \times 3}{21} \\ \\ \sf \implies \: \frac{14 + 3}{21} = \frac{17}{21} \\ \\ \green{ \sf{ \implies{ \frac{17}{21} \: \: \: ans..}}}$

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In the same concept you have to do it till (f) ...

Explanation :-

1. Firstly, take out the LCM of the denominators.
2. Then, multiply the numerators with the number which is obtained on dividing the denominator with the LCM.

Like,

3 is the denominator and LCM is 21 , so the number of obtained on dividing 3÷21 is 7. So, multiply the required number 7 with the given numerator as well done above....

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In no. (g) & (h) ... also (m) and (n).

we will apply the same concept but here we will subtract the final numerators.

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$\sf \: i) \: \frac{1}{2} + \frac{1}{3} + \frac{1}{6} \\ \\ \sf \implies \: LCM \: of \: 2,3 \: and \: 6 \: is \: 6. \\ \sf \implies \: \frac{1 \times3 + 1 \times 2 + 1 \times 1 }{6} \\ \\ \sf \implies \: \frac{3 + 2 + 1}{6} \\ \\ \sf \implies \: \frac{ \cancel6 \: ^{1} }{ \cancel6 \: ^{1} } \: \: \: \: \: \: \green {\sf = 1 \: \: \: ans..}$

In the same way, you have to do no. (j)

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$\sf \: k) \: 1 \frac{1}{3} + 3 \frac{2}{3} \\ \\ \sf \implies \: Change \: this \: mixed \: fraction \: into \: standard \: form. \\ \sf \implies \: \frac{4}{3} + \frac{11}{3} \\ \\ \sf \implies \: since \: it \: is \: a \: like \: fraction.. \: so \\ \sf \implies \: \frac{4 + 11}{3} \\ \\ \sf \implies \: \frac{ \cancel{15} \: ^{5} }{ \cancel3} \\ \\ \green{ \sf{ \implies{5 \: \: ans..}}}$

In the same way,

we'll do no. (l)

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TO CHANGE THE NUMBER FROM MIXED TO STANDARD FORM :-

$\sf \implies \: 1 \dfrac{ 1}{ 3} = 1 \dfrac{ + 1}{ \times 3} \\ \\ \sf \implies \: \frac{4}{3} ...$

We multiply the denominator 3 with 1 which gives 3 and then we add the required number i.e. 3 with the numerator 1 which gives 4 as answer, then we write this number 4 in the numerator and the denominator remains same.

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@MissSolitary ✌️

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