Question

${\huge {\boxed {\red {\mathcal {Yo}}}}}$

Factorie this : --
$a)9 {x}^{2} - 4 {y}^{2}$
$<marquee>Thanks❤<marquee>$​

Answer 1

$\bf\huge\underline{Solution :-}$

9x² - 4y²

= (3x)² - (2y)²

= (3x + 2y)(3x - 2y)

Here, Identity used :-

• a² - b² = (a + b)(a - b)

More identities :-

• (a + b)² = a² + b² + 2ab
• (a - b)² = a² + b² - 2ab

Answer 2

Answer:

${\boxed{\bold\green{Answer :(3x + 2y)(3x - 2y) }}}$

Step-by-step explanation:

Question:-

Factorize this:-

• a) $\sf\green{9{x}^{2} - 4{y}^{2}}$

$\bold{Solution:-}$

$\rm a) 9{x}^{2} - 4{y}^{2} \\\\\\\hookrightarrow\rm {(3x)}^{2} - {(2y)}^{2} \\\\\\\rm \: \: \: [\because ({a}^{2} - {b}^{2}) = (a + b) (a - b) ] \\\\\\\hookrightarrow{\boxed{\rm{ (3x + 2y)(3x - 2y) }}}$

$\boxed{\begin{minipage}{7 cm} More identities ralated to it :- \\\\{ {(a + b)}^{2} ={a}^{2} + {b}^{2} + 2ab }\\\\ { {(a - b)}^{2} ={a}^{2} + {b}^{2} - 2ab }\\\\{ {(a+b)}^{2} = {(a - b)}^{2} + 4ab }\\\\{ {(a - b)}^{2}= {(a + b)}^{2} - 4ab }\\\\{ {(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) }\\\\{ (x + a)(x + b) ={x}^{2} + (a + b)x + ab }\end{minipage}}$