Question

${ \huge{ \boxed{ \sf{ \blue{ question}}}}}$
answer this question
of MATH ➖
​

Answer 1

ANSWER = 35 , 65 , 13

$\huge\mathfrak\red{question}$

The sum of age of anup and his father is 100

When Anup is as old as his father now, he will be five times as old as his son Anuj is now. Anuj will be eight years older than Anup is now, when Anup is as old as his father.

$\huge\mathfrak\blue{Solution}$

Let the age of Anup be X

age of father = Y

given X + Y = 100

Y = 100 - X

When Anup will be old as father ,

his age = 100 - X

Difference between the ages

( 100 - X ) - X = 100 - 2X

Age of Anuj when Anup's age is fathers age

age = (100 - X) / 5

Age of Anuj when

Anup's age when he is in fathers age

, = [(100 - X )/5] + 100 - 2X

since this age is 8 years more than Anup's age ,

X + 8 = [( 100 - X )/5] + 100 - 2X

X + 8 = ( 100 - X + 500 - 10 X ) / 5

5X + 40 = 600 - 11 X

16 X = 560

X = 35 Years

Age of anup = 35 years

age of father = 65 years

age of anuj = 13 years

Answer 2

ANSWER = 35 , 65 , 13

question

The sum of age of anup and his father is 100

When Anup is as old as his father now, he will be five times as old as his son Anuj is now. Anuj will be eight years older than Anup is now, when Anup is as old as his father.

Solution

Let the age of Anup be X

age of father = Y

given X + Y = 100

Y = 100 - X

When Anup will be old as father ,

his age = 100 - X

Difference between the ages

( 100 - X ) - X = 100 - 2X

Age of Anuj when Anup's age is fathers age

age = (100 - X) / 5

Age of Anuj when

Anup's age when he is in fathers age

, = [(100 - X )/5] + 100 - 2X

since this age is 8 years more than Anup's age ,

X + 8 = [( 100 - X )/5] + 100 - 2X

X + 8 = ( 100 - X + 500 - 10 X ) / 5

5X + 40 = 600 - 11 X

16 X = 560

X = 35 Years

Age of anup = 35 years

age of father = 65 years

age of anuj = 13 years

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