Integrate. [cos^-1x (√1-x^2)]^-1 / logₑ{1+(sin(2x√1-x^2)/π}
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Salmon panna 2022 you can solve this question please try one..
Answers
Answered by
2
Let I=∫
1−x
2
xcos
−1
x
dx
I=
2
−1
∫
1−x
2
−2x
⋅cos
−1
xdx
Taking cos
−1
x as first function and (
1−x
2
−2x
) as second function and integrating by parts, we obtain I=
2
−1
[cos
−1
x∫
1−x
2
−2x
dx−∫{(
dx
d
cos
−1
x)∫
1−x
2
−2x
dx}dx]
=
2
−1
[cos
−1
x⋅2
1−x
2
−∫
1−x
2
−1
⋅2
1−x
2
dx]
=
2
−1
[2
1−x
2
cos
−1
x+∫2dx]
=
2
−1
[2
1−x
2
cos
−1
x+2x]+C
=−[
1−x
2
cos
−1
x+x]+C
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