Physics, asked by Anonymous, 3 months ago


 \huge \boxed{ \underline{\green{\bf QUESTION }}}
A circular coil of 50 turns and diameter 8 cm carries a current of 2 ampere. How much work
will be done in rotating the coil through 180°, when suspended in a uniform magnetic field of
0.1 Wb/m² ?​


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Answers

Answered by mushtaqsir4580
25

Answer:

A circular coil of radius 4 cm has 50 turns. In this coil a current of 2 A is flowing. It is placed in a magnetic field of 0.1 weber / m^2 . the moment ...

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Answered by aarti225566
11

Work done in rotating a coil through an angle θ from it's equilibrium position is W = MB(1 – cosθ) where θ = 180° and M

50 × 2 × ( 4 × 10^-2 )

50.24 × 10^-2A-m²

Hence W = 0.1J


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