A circular coil of 50 turns and diameter 8 cm carries a current of 2 ampere. How much work
will be done in rotating the coil through 180°, when suspended in a uniform magnetic field of
0.1 Wb/m² ?
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A circular coil of radius 4 cm has 50 turns. In this coil a current of 2 A is flowing. It is placed in a magnetic field of 0.1 weber / m^2 . the moment ...
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Work done in rotating a coil through an angle θ from it's equilibrium position is W = MB(1 – cosθ) where θ = 180° and M
50 × 2 × ( 4 × 10^-2 )
50.24 × 10^-2A-m²
Hence W = 0.1J
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