Science, asked by Anonymous, 8 months ago

$\huge\boxed{\underline{\mathcal{\red{Q} \green{U} \pink{ES} \orange{TI} \blue{O} \pink{N}}}}$
✊As ʟɪɢʜᴛ ғʀᴏᴍ ᴀ sᴛᴀʀ sᴘʀᴇᴀᴅs ᴏᴜᴛ ᴀɴᴅ ᴡᴇᴀᴋᴇɴs, ᴅᴏ ɢᴀᴘs ғᴏʀᴍ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇ ᴘʜᴏᴛᴏɴs?☃️

Answers

Answered by Anonymous

Answer:

$<body bgcolor= black><font color=yellow>$

$\huge{\underline{\underline{\mathfrak{\pink{Question:-}}}}}$

As ʟɪɢʜᴛ ғʀᴏᴍ ᴀ sᴛᴀʀ sᴘʀᴇᴀᴅs ᴏᴜᴛ ᴀɴᴅ ᴡᴇᴀᴋᴇɴs, ᴅᴏ ɢᴀᴘs ғᴏʀᴍ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇ ᴘʜᴏᴛᴏɴs?

$\huge{\underline{\underline{\mathfrak{\pink{Answer:-}}}}}$

When the light intensity gets weaker the statistical character of light becomes evident. The classical fields describe the average intensity but at low intensity you will increasingly see intensity fluctuations about this average. This phenomenon is called photon shot noise. If for example your detector detects an intensity corresponding to 10.000 photons during its integration time, then the intensity will follow a gaussian distribution with standard deviation of 100 or 1%. At even lower photon numbers poisson statistics applies. This is true for an incoherent source such as the star you mentioned, or a classical light bulb. You could say that between the individual photon detections there are gaps that display random length variation.

Therefore depends on the point of view from which you analyse it.

here your answer

Answered by rudrabhagat556

Answer:

nice answer

Explanation:

thanx me i m following u

Previous Question

Next Question

✊As ʟɪɢʜᴛ ғʀᴏᴍ ᴀ sᴛᴀʀ sᴘʀᴇᴀᴅs ᴏᴜᴛ ᴀɴᴅ ᴡᴇᴀᴋᴇɴs, ᴅᴏ ɢᴀᴘs ғᴏʀᴍ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇ ᴘʜᴏᴛᴏɴs?☃️​

Answers

As ʟɪɢʜᴛ ғʀᴏᴍ ᴀ sᴛᴀʀ sᴘʀᴇᴀᴅs ᴏᴜᴛ ᴀɴᴅ ᴡᴇᴀᴋᴇɴs, ᴅᴏ ɢᴀᴘs ғᴏʀᴍ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇ ᴘʜᴏᴛᴏɴs?

here your answer

$\huge\boxed{\underline{\mathcal{\red{Q} \green{U} \pink{ES} \orange{TI} \blue{O} \pink{N}}}}$
✊As ʟɪɢʜᴛ ғʀᴏᴍ ᴀ sᴛᴀʀ sᴘʀᴇᴀᴅs ᴏᴜᴛ ᴀɴᴅ ᴡᴇᴀᴋᴇɴs, ᴅᴏ ɢᴀᴘs ғᴏʀᴍ ʙᴇᴛᴡᴇᴇɴ ᴛʜᴇ ᴘʜᴏᴛᴏɴs?☃️