Question

$\huge\color{cyan}\boxed{\colorbox{black}{✿Question✿}}$

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 35 cm long, 30 cm wide and 25 cm high.
1) what is the area of the glass ?
2) What length of tape is needed for all the 12 edges?

${\bold{\red{❌No\:Spam❌}}}$​

Answer 1

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$\huge\color{cyan}\boxed{\colorbox{black}{Solution :}}$

${\bf{Given :}}$

Length $\implies$ 35 cm

Breadth $\implies$ 30 cm

and, Height $\implies$ 25 cm

${\bf{For\:the\:1st\:case :}}$

$\implies$Area of the Glass :

${\bold{\red{↦}}}$T.S.A of cuboid

${\bold{\red{↦}}}$2( lb + bh + lh)

${\bold{\red{↦}}}$2[ (35×30) + (30×25) + (35×25) ]

${\bold{\red{↦}}}$2( 1050 + 750 + 875 ) cm^2

${\bold{\red{↦}}}$5350 cm^2 ✔︎

$\implies$${\bf{For\:the\:2nd\:case :}}$

Length of tape needed for all 12 edges :

${\bold{\red{↦}}}$(perimeter of tap) + (perimeter of bottom) + (4 vertical edges)

${\bold{\red{↦}}}${2(l + b)+2(l + b)+(4h)}

${\bold{\red{↦}}}$4(35 + 30 + 25)cm

${\bold{\red{↦}}}$360 cm

${\bf{Required\: Answer :}}$

${\bold{\red{↦}}}$3 m & 60 cm✔︎

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Answer 2

Answer:

1. 5350cm^2
2. 360 cm

Step-by-step explanation:

Given :

Length = 35 cm

Breadth = 30 cm

Height = 25 cm

Solution

(i) Area of glass = total surface area of greenhouse

$= 2 (lb + bh + lh) \\ = 2 ( (35×30) + (30×25) + (35×25) ) \\ = 2 (1050 + 750 + 875 ) \\ = 5350 {cm}^{2}$

Therefore, area of glass is 4250 cm2.

(ii) Length of tape needed = perimeter of the greenhouse

= 4 (l + b + h)

= 4 (35 + 30 + 25) cm

= 360 cm.

Therefore, the length of tape needed is 360 cm.