Question

$\huge{ \color{green}\boxed{\boxed {\color{purple}{ \bf{Question}}}}}$
The length of a rectangular field is 72 m and the breadth is $\dfrac{4}{5}$ of its length find the area of the field.
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Need Proper/Explained answer.
Attach a diagram also..
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Answer 1

Given : The Length of a Rectangular field is 72 m & the breadth is $\sf\dfrac{4}{5}$ of its length.

Exigency To Find : Area of the Rectangular Field .

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❍ Length of Rectangular field is 72 m .

Given that ,

⠀⠀⠀⠀⠀The breadth of Rectangular feild is $\dfrac{4}{5}$ of its length .

Therefore,

• Breadth of Rectangular Field is $\bf\dfrac{4}{5} \times 72$

⠀⠀⠀⠀⠀Finding Area of Rectangular Field :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{Area _{(Rectangle)} \:: l \times b }\bigg\rgroup$

⠀⠀⠀⠀⠀Here l is the Length of Rectangular Field & b is the Breadth of Rectangular field.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad:\implies \sf Area = 72 \times \dfrac{4}{5} \times 72$

$\qquad:\implies \sf Area = 72 \times \dfrac{4}{\cancel {5}} \times \cancel {72}$

$\qquad:\implies \sf Area = 72 \times 4 \times 14.4$

$\qquad:\implies \sf Area = 72 \times 57.6$

$\qquad \longmapsto \frak{\underline{\purple{\:Area = 4,147.2\: m^2 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Area \:of\:Rectangular \:Field \:is\:\bf{4,147.2\:m^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\qquad \leadsto \sf Area_{(Rectangle)} = Length \times Breadth$

$\qquad \leadsto \sf Perimeter _{(Rectangle)} = 2 (Length + Breadth)$

$\qquad \leadsto \sf Area_{(Square)} = Side \times Side$

$\qquad \leadsto \sf Perimeter _{(Square)} = 4 \times Side$

$\qquad \leadsto \sf Area_{(Trapezium)} = \dfrac{1}{2} \times Height \times (a + b )$

$\qquad \leadsto \sf Area_{(Parallelogram)} = Base \times Height$

$\qquad \leadsto \sf Area_{(Triangle)} = \dfrac{1}{2} \times Base \times Height$

$\qquad \leadsto \sf Area_{(Rhombus)} = \dfrac{1}{2} \times Diagonal _{1}\times Diagonal_{2}$

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Answer 2

☞REFER TO THIS ATTACHMENT.

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AND ALSO GIVE ME THANKS..XD

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#THE GREAT SHREYA ❤️