Question

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A number is divided into two parts such that one part is 10 more than the other. If the two parts are in the ratio 5:3. Find the numbers.
[Hint. Let one number be x then the other number is x + 10 According to the problem x +10/x=5/3
Want handwritten solution ​

Answer 1

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Since,

The two parts are in the ratio 5:3,

Then,

Let the first number be 5x and second number be 3x.

As,

Second number is 10 more than the other, so it will be 3x+10.

→ 5x = 3x + 10

→ 5x - 3x = 10

→ 2x=10

→ x=5

The first number becomes 5 × (5)=25 and second number becomes 3 × (5) = 15.

The new number will be 25 + 15 = 40.

Hence our answer is 40.

$\huge\color{pink}\boxed{\colorbox{black}{@vikramjeeth}}$

Answer 2

Answer:

the two parts are in the ratio 5:3, Then let the first number be 5x and second number be 3x. According to the question, the second number is 10 more than the other, so it will be 3x+10.