Physics, asked by spbankingandsscserie, 19 days ago


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A physics student took a solid sphere of density 2 g cm–3 and radius 3.5 cm and applied a force on the sphere. If an acceleration of 1.5 cm s–2 is produced in it, find the amount of force applied on it.

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Answers

Answered by jurrykhan1289
2

Answer:

Force applied is 538.8 N

Explanation:

Force = Mass x Acceleration

To find mass we need to find volume of the sphere.

Radius (r) = 3.5 cm

Density = 2 g/cm^-3

Volume = (4/3) pi r^3

Volume = (4/3) pi 3.5^3

Volume = 179.6 cm^3

Density = Mass ÷ Volume

Mass = Density x Volume

Mass = 2 x 179.6

Mass = 359.2 g

Force = Mass x Acceleration

Force = 359.2 x 1.5

Force = 538.8 N

Answered by XxPratyakshxX
1

Explanation:

Given acceleration,a =1.5 cm(-2)

Radius of sphere,r=3.5cm

Density of sphere=2gcm -³

Force,F =(mass,m)(acceleration,a)

Mass=(Volume,V)(density)

Volume=4/3πr³

4/3*22/7*(3.5)³

Mass =[4/3*22/7*(3.5)³]*2

M=1078g/3

Force= (Mass)(Acceleration)

Force=1078/3*1.5

Force=1078/2=539 dyne

hello ridhima hope this helps you:)

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