Question

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The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30°. Find the height of the tower.

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Answer 1

Step-by-step explanation:

Base = 30m

Angle of elevation = 30⁰

let the height of tower be h.

then,

tan 30⁰ = Perpendicular/base

tan 30⁰ = h/30m

the value of tan 30⁰ is 1/√3

then,

$\frac{1}{ \sqrt{3} } = \frac{h}{30}$

$h = \frac{30}{ \sqrt{3} }$

~ 17.32 m

Answer 2

Answer:

Heya mate..here is your answer see the attachment..