Question

$\huge\color{pink}\mathfrak{Help Needed }$
${cot}^{2}θ - {tan}^{2} θ = {cosec}^{2} θ - {sec}^{2} θ$



As it ASAP​

Answer 1

Here I am using A instead of theta

we know the trigonometric identity

1 ) $\tt cot² A = cosec² A - 1$

2 ) $\tt tan² A = sec² A - 1$

$\tt = cot² A - tan² A$

$= ( cosec² A - 1 ) - ( sec² A - 1 )$

$\sf = cosec² A - 1 - sec² A + 1$

$\tt = cosec² A - sec² A$

$\tt = RHS$

Hence PROVED ✔️

I hope this helps uh!

$\sf{\blue{\underbrace{\underline{\orange{HENCE\; VERIFIED✓}}}}}$