Question

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${cot}^{2} θ \times {sec}^{2} θ \: = {cot}^{2} θ + 1$
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Answer 1

Answer

True

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cot²θ × sec²θ = cot²θ + 1

Manipulating right side

cot²θ + 1

rewrite

1 + cot²θ

Use pythagorean identity:

1+ cot²θ = csc²θ

convert to sines and cosines

apply reciprocal: csc² θ = (1/sinθ)²

1/sin²θ

Rewrite 1/sin²θ as cot²θ × sec²θ

Well

cot²θ sec²θ = cot²θ sec²θ

it proves that

LHS = RHS

All the best

@Rayyankashan❤

Answer 2

Answer:

hiii

Step-by-step explanation:

have a great day dear