Question

$\huge\color {purple}\boxed{\colorbox{black} { QUESTION♡}}$
The size of the perimeter of the square ABCD is equal to 100 cm. The length of the segment MN is equal to 5 cm and the triangle MNC is isosceles. Find the area of the pentagon ABNMD.

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Answer 1

Answer:

Right scalene triangle.

Sides: a = 3.536

  b = 3.536  

c = 5

Area: T = 6.25

Perimeter: p = 12.071

Semiperimeter: s = 6.036

Angle ∠ A = α = 45° = 0.785 rad

Angle ∠ B = β = 45° = 0.785 rad

Angle ∠ C = γ = 90° = 1.571 rad

*The perimeter is the continuous line forming the boundary of a closed geometric figure.

Square side AB = 100/4

AB = 25cm

Square area As = 25²

As = 625cm²

Triangle area At = [(sin45° * 5)²]/2

At = 6.25cm²

Area of ABNMD = As - At ABNMD = 618.75 cm² indecision

Area of the square - area of the triangle =100 - 6.25 =93.75 cm^2 - area of the pentagon ABNMD

Answer 2

Answer:

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