Question

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A block of wood of length 40 cm and area of cross section 15 cm² floats in water with ⅜ of its length above water. What is the density of wood ?
( Density of water = 1 g cm-³ )
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Answer 1

Explanation:

Relative density = Total volume of body/ Volume of body immersed

$Relative = 1− \frac{3}{8} = \frac{5}{8}$

So, density of wood = 5/8 × density of water

$=0.625×1g/cc$

$density  =0.625g/cc \: .$

hope it helps !!

thnku✌❤✌

Answer 2

Answer:

$relative \: density \: = \: \\ \\ \frac{volume \: of \: body \: immersed}{total \: volume \: of \: body \: } \\ \\ relative = 1 - \frac{3}{8} = \frac{5}{8} \\ \\ so \: density \: of \: wood \: = \frac{5}{8} \times density \: of \: water \\ \\ = \frac{0.625 \times 1g}{cc} \\ \\ density \: = \frac{0.625g}{cc}$

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