Question

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Derivation of kinetic energy ??? Don't copy paste !!


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Answer 1

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$\red{\underline{\underline{\huge\mathbb{DERIVATION\::}}}}$

Let us consider an object of m which is at rest lying on a table.

Let A force F acts on the object which moves the object through a distance S.

The workdone = $F \times S$

$\Rightarrow$W = $F_net \times s$ ----------- (1)

Let the work done on the object causes a change in its velocity from u to V and let a be the acceleration.

$\red{\underline{From\:\: Third\:\: equation\:\: of \:\:motion\:: }}$

$\Rightarrow$$V^2 - u^2 = 2as$

$\Rightarrow$s = $\frac{V^2 - u^2}{2a}$ ----------- (2)

$\red{\underline{By,\:Newton's\:\: second\:\: law\:\::}}$

$\Rightarrow$F = ma --------- (3)

$\red{\underline{From,\:equations\:\: (1)(2)\:\: and \:\:(3)\::}}$

$\Rightarrow$

W = $ma \times V^2 - \frac{u^2} {2a} = \frac {1}{2} m(V^2 - u^2)$

we know that the kinetic energy of a body moving with a certain velocity is equal to work done on the object to acquire that velocity from rest.

$\huge\sf\therefore K.E = \frac {1}{2} mv^2$

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~hope it helps ❤

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Answer 2

Answer:

The kinetic energy of a body is the energy that it possessed due to its motion. Kinetic energy can be defined as the work needed to accelerate an object of a given mass from rest to its stated velocity. If the velocity of the body is zero, then the kinetic energy will also be zero

Explanation:

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