Math, asked by sahvaishnavi7, 1 month ago

\huge\color{red}\boxed{\colorbox{Black}{question}}

Q.Find the torque acting on a rotating body, if it's angular momentum changes
from 5 kgm²/s to 8 kgm/s in 4 seconds.

A᭄ɴsᴡᴇʀ Correctly.​

Answers

Answered by kamalhajare543
39

Answer:

Question given:

  • Find the torque acting on a rotating body, if it's angular momentum changes from 5 kgm²/s to 8 kgm/s in 4 seconds

Information provided with us:

  • Angular momentum of of a rotating body changes from 5 kgm²/s to 8 ms²/s
  • Time taken is of 4 seconds

What we have to calculate:

  • We have to calculate and find out the torque which was acting on that rotating body.

Using Formula:

\red \bigstar \: \underline{ \boxed{\bf{τ \: = \: \dfrac{ \triangle L}{ \triangle \: T } }}}

Here,

  • L is distance
  • L is distanceF is magnitude
  • L is distanceF is magnitudeIt states that,

\tt{τ \: = \: \dfrac{Distance(L) _{f} - distance(L) _{1} } {time _{f} - time _{1} } }

Again where,

  • f is magnitude
  • f is magnitudeL is distance

f is magnitudeL is distanceWe have,

\star \: \tt{L _{f} \: is \: 8}⋆

\star \: \tt{L _{1} \: is \: 5}⋆

\star \: \tt{T _{f} \: is \: 4}

\star \: \tt{T _{1} \: is \: 0}⋆

\pink \bigstar \: \underline{ \underline{ \sf{Substituting \: the \: values \: we \: get:- }}}

: \longmapsto \: \tt{τ \: = \: \dfrac{8 - 5}{4-0} }:

On subtracting 8 with 5 we gets 3,

: \longmapsto \: \red{\boxed{\tt{τ \: = \: \dfrac{3}{4} }}}:

\underline{ \sf{ Hence, \: Torque \: acting \: on \: the \: rotating \: body \: is \: of \: \dfrac{3}{4}Nm}}

Thanks.

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