Question

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Answer 1

Answer:

$Given \:  AD  \: is \: bisector \:  ∠CAF</p><p></p><p></p><p>$

$to \: prove$

$\frac{ba}{ac} = \frac{bd}{dc}$

$Hence \:  ∠ACE=∠CAD \\  (Alternate interior angles)</p><p></p><p></p><p>$

$</p><p>∠AEC=∠FAD \\  (Corresponding angles)</p><p></p><p>$

$Thus, ∠AEC=∠ACE \\ ⇒AE=AC$

$Now \:  EC∥AD$

$Thus \: by \: basic \: proportional \\ \: theorem$

$( \frac{ba}{ae} ) = ( \frac{bd}{cd} )$

$</p><p>⇒(\frac{AC}{BA}) =(\frac{DC}{BD})  since AE=AC</p><p></p><p>$

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Answer 2

Answer:

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