Question

$\huge\color {white}\boxed{\colorbox{black} { QUESTION♡}}$
Initially the rectangular prism on the left was full of water. Then water was poured in the right cylindrical container so that the heights of water in both containers are equal. Find the height h of water in both containers.(round your answer to the nearest tenth of a cm).
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Answer 1

Answer:

Step-by-step explanation:

The volume of water in the rectangular prism inthe left is given

by2\ 4ltimes10=80 cm^ ^ 32*4*10=80cm 3

The volume of water in the middle rectangularprism in given by

2\times4\times h=80 h2*4* h=8Oh

The volume of water in cylinder on the right isgiven by

\pi\times (1)2\timesh = backslash pi \times h mathcal , backslash pi=; 3.14 pi*(1)2Vtim; sh = pi*h, pi = 3.14

Since all water in the container on the left ispoured in both containers on the right, then 80 cm^ ^ 3=8;

h+ \pi\times h80cm3=8h+xh

h= backslash frac\ 8O\ (8+ backslash pi)\ h= 80(8+T)

text[ value of; \ backslash pi=3.142 value of Pi = 3.142

On substituting the value we get,

h=lfrac\ 8O\ \ (8+3.142)\ = \frac c\ 80\\

11.142\ =7.18 cm

(8 + 3.142) 8011.14280= 7.18cm h =

7.2 cm (rounded to the nearest tenth of a cm).