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A tank contains molten brass having a composition of 20 kg of copper and 5 kg of zinc. A second tank contains molten brass of composition 30 kg of copper and 20 kg of zinc. How much molten brass should be taken from the first and second tanks, respectively, and kept in a third tank so that the final composition is 30 kg of copper and 12 kg of zinc? (i) 24 kg and 18 kg (iii) 10 kg and 32 kg (ii) 12 kg and 30 kg (iv) 21 kg and 21 kg???
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Answer 1

Explanation:

60 kg of alloy A has

lead and tin in the ratio of 3:2 so lead=60*3/5=36 kg

and tin=60*2/5=24kg.

100 kg of alloy B contains tin and copper in the ratio 1:4

so tin=100*1/5=20 kg

and copper=100*4/5=80 kg

so total tin on mixing the two

=24+20

=44 kg answer

Answer 2

Answer:

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