Question

$\huge\color {yellow}\boxed{\colorbox{black}{QUESTION♡}}$

write exponential form of
$9 \times 9 \times 9 \times 9$
taking the base as 3.

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Answer 1

Step-by-step explanation:

$9 \times 9 \times 9 \times 9 \times9$

$= {9}^{5}$

$= ({3}^{2} {)}^{5}$

$= {3}^{10}$

Hope it's helpful to you

Answer 2

Answer:

$\huge\color {pink}\boxed{\colorbox{black}{Solution♡}}$

We have,

$9 \times 9 \times 9 \times 9 \times$

$= {9}^{5}$

But we know that,

$9 = 3 \times 3 = {3}^{2}$

therefore,

${9}^{4} = ( { {3}^{2} })^{4} = {3}^{2 \times 4} = {3}^{8}$