Question

$\Huge\dag{\boxed{\sf{Question}}}$
In a $\triangle$ ABC, if 2 $\angle$A = 3 $\angle$B = 6 $\angle$C then calculate $\angle$A, $\angle$B and $\angle$C.​

Answer 1

Step-by-step explanation:

angle A = 90°

angle B = 60°

angle C = 30°

Answer 2

Solution

Given :-

• If given angle in any triangle in a relationship 2<A = 3<B = 6<C .

Find :-

• These all angles

Explanation

We Know,

$\dag\tt{\orange{\:Sum\:of\:all\:side\:=\:180}}$

So,Now

Let,

➠ 2<A = 3<B = 6<C = K.

Then,

• <A = K/2
• <B = K/3
• <C = K/6

So, We Have.

➠ <A + <B + <C = 180

➠ K/2 + K/3 + K/6 = 180

➠ (3K + 2K + K)/6 = 180

➠ 6k = 180 × 6

➠ K = 180 × 6 /6

➠ K = 180° .

So, Keep All Values.

For Angle <A .

• <A = 180/2 = 90°

For Angle <B .

• <B = 180/3 = 60°

For Angle <C.

• <C = 180/6 = 30°

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