Question

$\huge \dag \sf{Solve\:it}$​​

Answer 1

Answer:

So ∠ PQB = 90-x = ∠ BQT. In quadrilateral DCRT, ∠DRT = x = ∠DRS. So ∠DSR = 90 -x = ∠DSP. Hence PQRS is a parallelogram

Hope it may help you

Answer 2

Answer:

here is ur answer

Step-by-step explanation:

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